What must be subtracted from


What must be subtracted from 3a2 − 6ab − 3b2 − 1 to get 4a2 − 7ab − 4b2 + 1?


Let the required number be x">x.

$\left(3 a^{2}-6 a b-3 b^{2}-1\right)-x=4 a^{2}-7 a b-4 b^{2}+1$

$\left(3 a^{2}-6 a b-3 b^{2}-1\right)-\left(4 a^{2}-7 a b-4 b^{2}+1\right)=x$

$\therefore$ Required number $=-a^{2}+a b+b^{2}-2$



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