Question:
When a particle executes SHM, the nature of graphical representation of velocity as a function of displacement is :
Correct Option: , 2
Solution:
For a particle executing SHM,
$x=A \sin (\omega t+\phi)$
$V=\omega A \cos (\omega t+\phi)$
$\Rightarrow \frac{\mathrm{v}^{2}}{\omega^{2} \mathrm{~A}^{2}}+\frac{\mathrm{x}^{2}}{\mathrm{~A}^{2}}=1 \Rightarrow$ equation of ellipse between $v$ and $x$
Hence option (2)
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