Which of the following points lies on the tangent to

$x^{4} e^{y}+2 \sqrt{y+1}=3$

d.W.r. to $\mathrm{X}$

$x^{4} e^{y} y^{\prime}+e^{y} 4 x^{3}+\frac{2 y^{\prime}}{2 \sqrt{y+1}}=0$

at $\mathrm{P}(1,0)$

$y_{P}^{\prime}+4+y_{P}^{\prime}=0$

$\Rightarrow y_{P}^{\prime}=-2$

Tangent at $\mathrm{P}(1,0)$ is

$y-0=-2(x-1)$

$2 x+y-2$

$(-2,6)$ lies on it