Which term of the AP 72, 68, 64, 60,… is 0?
Question:

Which term of the AP 72, 68, 64, 60,… is 0?

Solution:

In the given AP, first term, a = 72 and common difference, d = (68 – 72) = -4.
Let its nth term be 0.
Then, Tn = 0  
⇒ a + (n – 1)d = 0
⇒ 72 + (– 1) ⨯ (-4) = 0
⇒ 76 – 4n = 0
⇒ 4n = 76
⇒ n = 19
Hence, the 19th term of the given AP is 0.

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