Write a value

Question:

Write a value of $\int \tan x \sec ^{3} x d x$.

Solution:

given $\int \tan x \sec ^{3} x d x$

$=\int(\tan x \sec x) \sec ^{2} x d x$

Let $\sec x=t$

Differentiating on both sides we get,

$\tan x \sec x d x=d t$

Substituting above equation in $\int \tan x \sec ^{3} x d x$ we get,

$=\int t^{2} d t$

$=\frac{t^{3}}{3}+c$

$=\frac{\sec ^{3} x}{3}+c$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now