Question:
Write a value of $\int \tan ^{6} x \sec ^{2} x d x$
Solution:
let $\tan x=t$
Differentiating on both sides we get,
$\sec ^{2} x d x=d t$
Substituting above equation in $\int \tan ^{3} x \sec ^{2} x d x$ we get,
$=\int t^{6} d t$
$=\frac{t^{7}}{7}+c$
$=\frac{\tan ^{7} x}{7}+c$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.