Write a value


Write a value of $\int \tan ^{6} x \sec ^{2} x d x$


let $\tan x=t$

Differentiating on both sides we get,

$\sec ^{2} x d x=d t$

Substituting above equation in $\int \tan ^{3} x \sec ^{2} x d x$ we get,

$=\int t^{6} d t$


$=\frac{\tan ^{7} x}{7}+c$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now