Write the balanced chemical equations for

Question:

Write the balanced chemical equations for the following reactions and identify the type of reaction in each

(a) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773 K to form ammonia gas.

(b) Potassium hydroxide solution is treated with acetic acid to form potassium acetate and water.

(c) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4.

(d) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and to release heat and light. Catalyst (Pt)

Solution:

(a) $\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \stackrel{\text { Catalyst(Pt) }}{\stackrel{773 \mathrm{~K}}{\longrightarrow}} 2 \mathrm{NH}_{3}(g)$                            Combination reaction

              Double displacement or neutralisation reaction.

 

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now