Write the balanced chemical equations for the following reactions
(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogen carbonate.
(b) Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.
(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide (Cu2I2), liberates iodine gas and also forms potassium sulphate.
Identify the reducing agent in the following reactions
(a) Na2CO3 (s) + HCl (aq) ———–> NaCl(aq) + NaHCO3 (aq)
(b) NaHCO3 (s) + HCl (aq) ———–> NaCl(aq) + H2O (aq) + CO2(g)
(c) 2CuSO4 (s) + 4KI (aq) ———–> Cu2I2 (s) + 2K2SO4 (aq) + I2 (g)
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.