Question:
Write the value of $\sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)$
Solution:
$\sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)=\sin ^{-1}\left[\sin \left(\pi-\frac{2 \pi}{5}\right)\right]$
$=\sin ^{-1}\left(\sin \frac{2 \pi}{5}\right)$
$=\frac{2 \pi}{5}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.