Question:
Write the zeros of the polynomial $x^{2}-x-6$
Solution:
$f(x)=x^{2}-x-6$
$=x^{2}-3 x+2 x-6$
$=x(x-3)+2(x-3)$
$=(x-3)(x+2)$
$f(x)=0 \Rightarrow(x-3)(x+2)=0$
$\Rightarrow(x-3)=0$ or $(x+2)=0$
$\Rightarrow x=3$ or $x=-2$
So, the zeros of f(x) are 3 and −2.
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