Q. The equation of the tangent to the curve $y=x+\frac{4}{x^{2}},$ that is parallel to the x-axis, is :-
(1) y = 0 (2) y = 1 (3) y = 2 (4) y = 3
[AIEEE-2010]
Q. The intercepts on x-axis made by tangents to the curve, $\mathrm{y}=\int_{0}^{\mathrm{x}}|\mathrm{t}| \mathrm{dt}, \mathrm{x} \in \mathrm{R}$ which are parallel to the line y = 2x, are equal to
$(1) \pm 1$ $(2) \pm 2$ (3) $\pm 3$ (4) $\pm 4$
[JEE-MAIN 2013]
Q. The normal to the curve, $x^{2}+2 x y-3 y^{2}=0,$ at $(1,1):$
(1)meets the curve again in the third quadrant
(2) meets the curve again in the fourth quadrant
(3) does not meet the curve again
(4) meets the curve again in the second quadrant
[JEE-MAIN 2015]
Q. Consider $f(x)=\tan ^{-1}(\sqrt{\frac{1+\sin x}{1-\sin x}}), x \in\left(0, \frac{\pi}{2}\right) .$ A normal to $y=f(x)$ at $x=\frac{\pi}{6}$ also passes through the point :
( 1)$\left(\frac{\pi}{4}, 0\right)$b
(2) (0, 0)
(3) $\left(0, \frac{2 \pi}{3}\right)$
(4) $\left(\frac{\pi}{6}, 0\right)$
[JEE-MAIN 2016]
Q. If the curves $\mathrm{y}^{2}=6 \mathrm{x}, 9 \mathrm{x}^{2}+\mathrm{by}^{2}=16$ intersect each other at right angles, then the value of $\mathrm{b}$ is :
(1) $\frac{7}{2}$ (2) 4 (3) $\frac{9}{2}$ (4) 6
[JEE-MAIN 2016]
Oh bhai 2016 ke aage bhi badho 2021 ke bhi 2 session ho chuke tum itne pichde kyu ho
Op questions
nice
thanx
Good to see all questions here
it is a good platform but no of questions are quite less …
2 nd last question
THANKS…FOR ….QUESTIONS
👍👍
Op questions
plz can u explain second last question more properly??
U just differentiate given f(x) u will get slope of tangent we known (slopeoftangent*slopeofnormal=-1) from here u get slope of normal they gave x value find y value by sub in eqn of curve then apply normal eqn then sub option one by one u will get answer !
good but need some more problems..
Yes
Good but some more prblms
well gud can have more stuff and content
well gud can have more stuff and content
Fuck this website
Some more
Thank you