Q. The equation of the tangent to the curve $y=x+\frac{4}{x^{2}},$ that is parallel to the x-axis, is :-
(1) y = 0 (2) y = 1 (3) y = 2 (4) y = 3

**[AIEEE-2010]**
Q. The intercepts on x-axis made by tangents to the curve, $\mathrm{y}=\int_{0}^{\mathrm{x}}|\mathrm{t}| \mathrm{dt}, \mathrm{x} \in \mathrm{R}$ which are parallel to the line y = 2x, are equal to
$(1) \pm 1$ $(2) \pm 2$ (3) $\pm 3$ (4) $\pm 4$

**[JEE-MAIN 2013]**
Q. The normal to the curve, $x^{2}+2 x y-3 y^{2}=0,$ at $(1,1):$
(1)meets the curve again in the third quadrant
(2) meets the curve again in the fourth quadrant
(3) does not meet the curve again
(4) meets the curve again in the second quadrant

**[JEE-MAIN 2015]**
Q. Consider $f(x)=\tan ^{-1}(\sqrt{\frac{1+\sin x}{1-\sin x}}), x \in\left(0, \frac{\pi}{2}\right) .$ A normal to $y=f(x)$ at $x=\frac{\pi}{6}$ also passes through the point :
( 1)$\left(\frac{\pi}{4}, 0\right)$b
(2) (0, 0)
(3) $\left(0, \frac{2 \pi}{3}\right)$
(4) $\left(\frac{\pi}{6}, 0\right)$

**[JEE-MAIN 2016]**
Q. If the curves $\mathrm{y}^{2}=6 \mathrm{x}, 9 \mathrm{x}^{2}+\mathrm{by}^{2}=16$ intersect each other at right angles, then the value of $\mathrm{b}$ is :
(1) $\frac{7}{2}$ (2) 4 (3) $\frac{9}{2}$ (4) 6

**[JEE-MAIN 2016]**
Oh bhai 2016 ke aage bhi badho 2021 ke bhi 2 session ho chuke tum itne pichde kyu ho

Op questions

nice

thanx

Good to see all questions here

it is a good platform but no of questions are quite less …

2 nd last question

THANKS…FOR ….QUESTIONS

👍👍

Op questions

plz can u explain second last question more properly??

U just differentiate given f(x) u will get slope of tangent we known (slopeoftangent*slopeofnormal=-1) from here u get slope of normal they gave x value find y value by sub in eqn of curve then apply normal eqn then sub option one by one u will get answer !

good but need some more problems..

Yes

Good but some more prblms

well gud can have more stuff and content

well gud can have more stuff and content

Fuck this website

Some more

Thank you