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*Simulator*

**Previous Years AIEEE/JEE Main Questions**

(1) 400 R (2) 500 R (3) 200 R (4) 300

** [AIEEE-2009]**

**Sol.**(1)

(1) –690 R (2) +690 R (3) –414 R (4) +414 R

**[AIEEE-2009]**

**Sol.**(4)

(1) 1076 R (2) 1904 R (3) Zero (4) 276 R

** [AIEEE-2009]**

**Sol.**(4)

(1) 0.25 (2) 0.5 (3) 0.75 (4) 0.99

**[AIEEE-2010]**

**Sol.**(3)

by $62 \mathrm{K},$ its efficiency increases to $\frac{1}{3} .$ Then $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ are, respectively:-

(1) 330 K and 268 K (2) 310 K and 248 K (3) 372 K and 310 K (4) 372 K and 330 K

**[AIEEE-2011]**

**Sol.**(3)

(1) equal to 0.002 kJ

(2) greater than 0.148 kJ

(3) between 0.148 kJ and 0.028 kJ

(4) less than 0.028 kJ

**[AIEEE-2011]**

**Sol.**(3)

(1) $\frac{\mathrm{P}}{2}, \mathrm{T}$

(2) $\frac{\mathrm{P}}{2}, \frac{\mathrm{T}}{2}$

(3) P, T

(4) $\mathrm{P}, \frac{\mathrm{T}}{2}$

** [AIEEE-2011]**

**Sol.**(1)

**[AIEEE-2012]**

**Sol.**(2)

(1) 600 K

(2) efficiency of Carnot engine cannot be made larger than 50%

(3) 1200 K

(4) 750 K

** [AIEEE-2012]**

**Sol.**(4)

(1) $\mathrm{p}_{0} \mathrm{v}_{0}$

( 2)$\left(\frac{13}{2}\right) \mathrm{p}_{0} \mathrm{v}_{0}$

( 3)$\left(\frac{11}{2}\right) \mathrm{p}_{0} \mathrm{v}_{0}$

(4) $4 \mathrm{p}_{0} \mathrm{v}_{0}$

**[jEE-Mains-2013]**

**Sol.**(2)

**[jEE-Mains-2014]**

**Sol.**(2)

(1) $\mathrm{T} \propto \frac{1}{\mathrm{R}}$

(2) $\mathrm{T} \propto \frac{1}{\mathrm{R}^{3}}$

(3) T $\propto \mathrm{e}^{-\mathrm{R}}$

(4) $\mathrm{T} \propto \mathrm{e}^{-3 \mathrm{R}}$

**[jEE-Mains-2015]**

**Sol.**(1)

(1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (1) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{\mathrm{nR}}$ (3) $\frac{3 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$ (4) $\frac{9 \mathrm{P}_{0} \mathrm{V}_{0}}{2 \mathrm{nR}}$

**[jEE-Mains-2016]**

**Sol.**(2)

(1) $\mathrm{n}=\frac{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}{\mathrm{C}-\mathrm{C}_{\mathrm{P}}}$

(2) $\mathrm{n}=\frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}$

(3) $\quad \mathrm{n}=\frac{\mathrm{C}-\mathrm{C}_{\mathrm{P}}}{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}$

(4) $\mathrm{n}=\frac{\mathrm{C}_{\mathrm{P}}-\mathrm{C}}{\mathrm{C}-\mathrm{C}_{\mathrm{V}}}$

**[jEE-Mains-2016]**

**Sol.**(3)

$\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=$ = a for hydrogen gas $\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=$ = b for nitrogen gas The correct relation between a and b is :

(1) a = 14 b

(2) a = 28 b

(3) $a=\frac{1}{14} b$

(4) a = b

**[jEE-Mains-2017]**

**Sol.**(1)

(1) (a) 195 K (b) –2.7 kJ

(2) (a) 189 K (b) –2.7 kJ

(3) (a) 195 K (b) 2.7 kJ

(4) (a) 189 K (b) 2.7 kJ

**[jEE-Mains-2018]**

**Sol.**(2)