Alternating Current – JEE Main Previous Year Questions with Solutions
JEE Main Previous Year Question of Physics with Solutions are available here. Practicing JEE Main Previous Year Papers Questions of Physics will help all the JEE aspirants in realizing the question pattern as well as help in analyzing their weak & strong areas. Get detailed Class 11th &12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc. eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects. Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more. Download eSaral app for free study material and video tutorials.
Q. In a series LCR circuit R = $200 \Omega$ and the voltage and the frequency of the main supply is 220 V and 50 Hz respectively. On taking out the capacitance from the circuit the current lages behind the voltage by $30^{\circ}$. On taking out the inductor from the circuit the current leads the voltage by $30^{\circ}$. The power dissipated in the LCR circuit is : (1) 242 W (2) 305 W (3) 210 W (4) Zero W [AIEEE – 2010]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (1)

Q. A fully charged capacitor C with intial charge $\mathrm{q}_{0}$ is connected to a coil of self inductance L at t = 0. The time at which the energy is stored equally between the electric and the magnetic fields is :- (1) $2 \pi \sqrt{\mathrm{LC}}$ (2) $\sqrt{1 C}$ (3) $\pi \sqrt{\mathrm{LC}}$ (4) $\frac{\pi}{4} \sqrt{\mathrm{LC}}$ [AIEEE – 2011]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (4)

Q. In an LCR circuit as shown below both switches are open initially. Now switch S1 is closed, $\mathrm{S}_{2}$ kept open, (q is charge on the capacitor and $\tau=\mathrm{RC}$ is Capacitive time constant). Which of the following statement is correct? (1) Work done by the battery is half of the energy dissipated in the resistor (2) At t $=\tau, q=C \sqrt{/ 2}$ (3) At $\mathrm{t}=2 \pi, \mathrm{q}=\mathrm{CV}\left(1-\mathrm{e}^{-2}\right)$ (4) At $\mathrm{t}=\frac{\tau}{2}, \mathrm{q}=\mathrm{CV}\left(1-\mathrm{e}^{-1}\right)$ [JEE Main-2013]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (3)

Q. An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to $\mathrm{Q}_{0}$ and then connected to the L and R as shown below. If a student plots graphs of the square of maximum charge on the capacitor with time (t) for two different values $\mathrm{L}_{1}$ and $\mathrm{L}_{2}\left(\mathrm{L}_{1}>\mathrm{L}_{2}\right)$ of L then which of the following represents this graph correctly ? (plots are schematic and not drawn to scale) [JEE Main-2015]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (3) As damping is happening its amplitude would vary as The oscillations decay exponentially and will be proportional to $\mathrm{e}^{-\gamma t}$ where $\gamma$ depends inversely on L. So as inductance increases decay becomes slower  for

Q. An arc lamp requires a direct current of 10A at 80V to function. If it is connected to a 220V (rms), 50 Hz AC supply, the series inductor needed for it to work is close to :- (1) 0.065 H (2) 80 H (3) 0.08 H (4) 0.044 H [JEE Main-2016]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (1) As damping is happening its amplitude would vary as The oscillations decay exponentially and will be proportional to $\mathrm{e}^{-\gamma t}$ where $\gamma$ depends inversely on L. So as inductance increases decay becomes slower  for

Q. For an RLC circuit driven with voltage of amplitude $\mathrm{v}_{\mathrm{m}}$ and frequency $\mathrm{w}_{0}=\frac{1}{\sqrt{\mathrm{LC}}}$ the current exhibits resonance. The quality factor, Q is given by : (1) $\frac{\omega_{0} \mathrm{R}}{\mathrm{L}}$ ( 2)$\frac{\mathrm{R}}{\left(\omega_{0} \mathrm{C}\right)}$ (3) $\frac{\mathrm{CR}}{\omega_{0}}$ (4) $\frac{\omega_{0} \mathrm{L}}{\mathrm{R}}$ [JEE Main-2018]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (4) Quality factor $=\frac{\omega_{0} \mathrm{L}}{\mathrm{R}}$

Q. In an a. c. circuit, the instantaneous e.m.f. and current are given by e = 100 sin 30 t i = 20 sin $\left(30 t-\frac{\pi}{4}\right)$ In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively. (1) $\frac{1000}{\sqrt{2}}, 10$ (2) $\frac{50}{\sqrt{2}}, 0$ (3) 50, 0 (4) 50, 10 [JEE Main-2018]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (1)

• August 6, 2021 at 11:11 am

Sir Update bhi krdo PYQS 2020 aur 21 ke plz

4
• July 11, 2021 at 10:40 pm

Keep some more interesting questions along with these…

1
• April 30, 2021 at 7:36 pm

thank you

1
• April 26, 2021 at 12:26 pm

gd questions

1
• January 22, 2021 at 11:23 am

Thank you

6
• December 9, 2020 at 6:25 pm

4
• October 29, 2020 at 1:53 pm

Thanks Buddy. Whatever question are there……They are quality based. Easy, Medium, Hard sab h. Thanks mate.

3
• October 20, 2020 at 5:24 pm

Nice questions . Thanks for help.

11
• September 17, 2020 at 11:04 am

ques quantity was quite less

7
• August 31, 2020 at 7:34 am

It would be nice if you add 2019&20 questions

17
• October 10, 2020 at 12:58 pm

Aur que nhi h kya sir… I effective se related

2
• August 29, 2020 at 7:01 pm

Arey bhenchod. Tu bhi previous year questions dekh ke exam dene jayega

4
• August 27, 2020 at 7:48 pm

Maa chudi padi hai yaha par

2
• August 27, 2020 at 10:20 am

Thanks for the help.

0
• July 4, 2020 at 7:16 pm

Good things

0
• June 8, 2020 at 3:44 pm

Please make sure that the mathematical terms are correct and please correct the overlapings. Other than this all is well. THANK YOU

0
• May 29, 2020 at 3:00 pm

Bcdbhfbf

0
• December 25, 2019 at 8:47 pm

was really interesting

21