Q. Match each of the diatomic molecules in Column I with its property / properties in Column II.
[JEE 2009]

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Sol. $A \rightarrow P, Q, R, S$ $B \rightarrow Q, R, S, T$ $C \rightarrow P, Q, R$ $D \rightarrow P, Q, R, S$

Q. The nitrogen oxide(s) that contain(s) N–N bond(s) is (are)
(A) $\mathrm{N}_{2} \mathrm{O}$
(B) $\mathrm{N}_{2} \mathrm{O}_{3}$
(C) $\mathrm{N}_{2} \mathrm{O}_{4}$
(D) $\mathrm{N}_{2} \mathrm{O}_{5}$
[JEE 2009]
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Sol. (A,B,C)

Q. In the reaction
$2 \mathrm{X}+\mathrm{B}_{2} \mathrm{H}_{6} \longrightarrow\left[\mathrm{BH}_{2}(\mathrm{X})_{2}\right]^{+}\left[\mathrm{BH}_{4}\right]^{-}$
the amine(s) X is (are)
(A) $\mathrm{NH}_{3}$
(B) $\mathrm{CH}_{3} \mathrm{NH}_{2}$
(C) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}$
$(\mathrm{D})\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}$
[JEE 2009]
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Sol. (B,C)

Q. The number of water molecule(s) directly bonded to the metal centre in $\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}$ is
[JEE 2009]
Q. The species having pyramidal shape is
(A) $\mathrm{SO}_{3}$
(B) $\operatorname{BrF}_{3}$
(C) $\mathrm{SiO}_{3}^{2-}$
(D) $\mathrm{OSF}_{2}$
[JEE 2010]
Q. Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule $\mathrm{B}_{2}$ is
(A) 1 and diamagnetic
(B) 0 and diamagnetic
(C) 1 and paramagnetic
(D) 0 and paramagnetic
[JEE 2010]
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Sol. (A) If Hund’s rule is violated in Boron then unpaired electron of

Q. Based on VSEPR theory, the number of 90 degree F–Br–F angles in $\mathrm{BrF}_{5}$ is
[JEE 2010]
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Sol. 0

Q. The value of n in the molecular formula $\mathrm{Be}_{\mathrm{n}} \mathrm{Al}_{2} \mathrm{Si}_{6} \mathrm{O}_{18}$ is
[JEE 2010]
Q. The total number of diprotic acids among the following is
[JEE 2010]

Q. Among the following, the number of elements showing only one non-zero oxidation
state is
O, Cl, F, N, P, Sn, Tl, Na, Ti
[JEE 2010]
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Sol. 2 Na & F
Q. The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}_{2} \mathrm{S}_{4} \mathrm{O}_{6}$ is.
[JEE 2011]
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Sol. 5 $\mathrm{Na}_{2} \mathrm{S}_{4} \mathrm{O}_{6}$

Q. Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen-
(A) $\mathrm{HNO}_{3}, \mathrm{NO}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{N}_{2}$
(B) $\mathrm{HNO}_{3}, \mathrm{NO}, \mathrm{N}_{2}, \mathrm{NH}_{4} \mathrm{Cl}$
(C) $\mathrm{HNO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{NO}, \mathrm{N}_{2}$
(D) $\mathrm{NO}, \mathrm{HNO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{N}_{2}$
[JEE 2012]
Q. In allene $\left(\mathrm{C}_{3} \mathrm{H}_{4}\right)$, the type(s) of hybridisation of the carbon atoms is (are)
(A) sp and $\mathrm{sp}^{3}$
(B) sp and $\mathrm{sp}^{2}$
(C) only $\mathrm{sp}^{2}$
(D) $\mathrm{sp}^{2}$ and $\mathrm{sp}^{3}$
[JEE 2012]
Q. The shape of $\mathrm{XeO}_{2} \mathrm{F}_{2}$ molecule is :
(A) Trigonal bipyramidal
(B) Square planar
(C) tetrahedral
(D) see-saw
[JEE 2012]
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Sol. (D)

Q. The total number of lone-pairs of electrons in melamine is
[JEE Adv. 2013]
Q. Assuming 2s-2p mixing is NOT operative, the paramagnetic species among the following is
(A) $\mathrm{Be}_{2}$
(B) $\mathrm{B}_{2}$
(C) $\mathrm{C}_{2}$
(D) $\mathrm{N}_{2}$
[JEE Adv. 2014]
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Sol. (C) If 2s–2p is not operative than $\mathrm{C}_{2}$ becomes paramagnetic.
Q. Match the orbital overlap figures shown in List-I with the description given in List-II and select the correct answer using the code given below the lists.
[JEE Adv. 2014]


Q. The compound(s) with TWO lone pairs of electrons on the central atom is(are) –
(A) $\mathrm{BrF}_{5}$
(B) $\mathrm{ClF}_{3}$
(C) $\mathrm{XeF}_{4}$
(D) SF $_{4}$
[JEE – ADV. 2016]
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Sol. (B,C)



Q. The crystalline form of borax has
(A)Tetranuclear$\left[\mathrm{B}_{4}\mathrm{O}_{5}(\mathrm{OH})_{4}\right]^2-}$ unit
(B) All boron atoms in the same plane
(C) Equal number of $\operatorname{sp}^{2}$ and $\mathrm{sp}^{3}$ hybridized boron
atoms
(D) One terminal hydroxide per boron atom
[JEE – ADV. 2016]
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Sol. (A,C,D)

Q. According to Molecular Orbital Theory,
(A) $\mathrm{C}_{2}^{2-}$ is expected to be diamagnetic
(B) $\mathrm{O}_{2}^{2+}$ is expected to have a longer bond length than O2
(C) $\mathrm{N}_{2}^{+}$ and $\mathrm{N}_{2}$– have the same bond order
(D) $\mathrm{He}_{2}^{+}$ has the same energy as two isolated He atoms
[JEE – ADV. 2016]
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Sol. (A,C)


Q. The correct statements(s) about the oxoacids, $\mathrm{HClO}_{4}$ and HClO, is (are) –
(A) $\mathrm{HClO}_{4}$ is more acidic than HClO because of the resonance stabilization of its anion
(B) $\mathrm{HClO}_{4}$ is formed in the reaction between $\mathrm{Cl}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$
(C) The central atom in Both $\mathrm{HClO}_{4}$ and HClO is $\mathrm{sp}^{3}$ hybridized
(D) The conjugate base of $\mathrm{HClO}_{4}$ is weaker base than $\mathrm{H}_{2} \mathrm{O}$
[JEE – Adv. 2017]
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Sol. (A,C,D)


Q. The colour of the $\mathrm{X}_{2}$ molecules of group 17 elements changes gradually from yellow to violet down the group. This is due to –
A) the physical state of $\mathrm{x}_{2}$ at room temperature changes from gas to solid down the group
(B) decrease in HOMO-LUMO gap down the group
(C) decrease in
down the group
(D) decrease in ionization energy down the group
[JEE – Adv. 2017]

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Sol. (B,C)

Q. Among$\mathrm{H}_{2},\mathrm{He}_{2}^{+},\mathrm{Li}_{2},\mathrm{Be
_{2},\mathrm{B}_{2},\mathrm{C}_{2}, \mathrm{N}_{2}, \mathrm{O}_{2}^{-}$ the
number of diamagnetic species is –
(Atomic number) : H = 1, He = 2, Li = 3, Be = 4, B = 5, C = 6, N = 7, O = 8 , f = 9)
[JEE – Adv. 2017]
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Sol. 5or6

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is.
$\left[\mathrm{TeBr}_{6}\right]^{2-},\left[\mathrm{BrF}_{2}\right]^{+}, \mathrm{SNF}_{3}$ and $\left[\mathrm{XeF}_{3}\right]^{-}$
[Atomic number : N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54]
[JEE – Adv. 2017]
Q. The order of the oxidation state of the phosphorus atom in $\mathrm{H}_{3} \mathrm{PO}_{2}, \mathrm{H}_{3} \mathrm{PO}_{4}, \mathrm{H}_{3} \mathrm{PO}_{3}$ and $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}$ is
(A) $\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}$
(B) $\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}$
(C) $\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}>\mathrm{H}_{3} \mathrm{PO}_{4}$
(D) $\mathrm{H}_{3} \mathrm{PO}_{4}>\mathrm{H}_{3} \mathrm{PO}_{2}>\mathrm{H}_{3} \mathrm{PO}_{3}>\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}$
[JEE – Adv. 2017]
Q. The option(s) with only amphoteric oxides is (are)
(A) $\mathrm{Cr}_{2} \mathrm{O}_{3}, \mathrm{CrO}, \mathrm{SnO}, \mathrm{PbO}$
(B) $\mathrm{NO}, \mathrm{B}_{2} \mathrm{O}_{3}, \mathrm{PbO}, \mathrm{SnO}_{2}$
(C) $\mathrm{Cr}_{2} \mathrm{O}_{3}, \mathrm{BeO}, \mathrm{SnO}, \mathrm{SnO}_{2}$
(D) $\mathrm{ZnO}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{PbO}, \mathrm{PbO}_{2}$
[JEE – Adv. 2017]
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Sol. (A,C)

Q. Among the following, the correct statement(s) is are
(A) $\mathrm{Al}\left(\mathrm{CH}_{3}\right)_{3}$ has the three-centre two-electron
bonds in its dimeric structure
(B) $\mathrm{AlCl}_{3}$ has the three-centre two-electron bonds in its dimeric structure
(C) BH3 has the three-centre two-electron bonds in its dimeric structure
(D) The Lewis acidity of $\mathrm{BCl}_{3}$ is greater than that of $\mathrm{AlCl}_{3}$
[JEE – Adv. 2017]
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Sol. (A,C,D) (A)



Q. Based on the compounds of group 15 elements , the correct statement(s) is (are)
(A) $\mathrm{Bi}_{2} \mathrm{O}_{5}$ is more basic than $\mathrm{N}_{2} \mathrm{O}_{5}$
(B) $\mathrm{NF}_{3}$ is more covalent than $\mathrm{BiF}_{3}$
(C) PH3 boils at lower temperature than $\mathrm{NH}_{3}$
(D) The N–N single bond is stronger than the P–P single bond
[JEE – Adv. 2018]
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Sol. (A,B,C)

abey tumhare baap ka property hai ki copy option block karke rakhe ho. bake question chapterwise segregate karke achcha kiye ho. god bless you
Sounds great ,wishing to uptade even recent papers
Very Helpful, Much Appreciated, Thank You!
Thanks 😊
thanks to you
Good
nice
THANKU SIR FOR THE ABOVE THEY ARE EASY SUMS