Chemical Kinetics - JEE Advanced Previous Year Questions with Solutions
Practice Chemical Kinetics with JEE Advanced previous year questions and detailed solutions to strengthen concepts of reaction rates, order, Arrhenius equation, and kinetics problem-solving.
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Simulator Previous Years JEE Advance Questions 
[JEE 2010] 
assuming A and $\mathrm{E}_{\mathrm{a}}$ to be constant theoretically, the plot should be 
But
No such option is given. Now experimentally, A and $\mathrm{E}_{\mathrm{a}}$ both vary with temperature and k increases as T increases and become very large at infinite temperature. Hence option (A) is correct. 
[JEE 2010] 
Zero order reaction because rate is constant with time. Alternative solution : By hit and trial method, assuming the reaction is of zero order, putting given data in integrated expression for zero order. 
the value of k is same from different data so reaction is zero order reaction. 
the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is - (A) 2 (B) 3 (C) 0 (D) 1 [JEE 2013] 
If this reaction is conducted at $\left(P, T_{2}\right)$, with $\mathrm{T}_{2}>\mathrm{T}_{1}$, the % yield of ammonia as a function of time is represented by – 
[JEE 2015] 
$\therefore$ % yield will increase in initial stages due to increase in net speed As time proceeds $\Rightarrow \mathrm{r}_{\mathrm{net}}=\mathrm{k}_{\mathrm{f}}\left[\mathrm{N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}-\mathrm{k}_{\mathrm{b}}\left[\mathrm{NH}_{3}\right]^{2}$ On increasing temp., $\mathrm{k}_{\mathrm{f}} \& \mathrm{k}_{\mathrm{b}}$ increase but increase of $\mathrm{k}_{\mathrm{b}}$ is more so % yield will decrease % yield will increase in initial stage due to enhance speed but as time proceeds , final yield is governed by thermodynamics due to which yield decrease since reaction is exothermic 
[JEE Advance 2018] 
Frequently Asked Questions
Find answers to common questions.
How many questions from Chemical Kinetics appear in JEE Advanced each year?
Typically, 1–2 questions appear from Chemical Kinetics in JEE Advanced annually. They are often in integer-answer or multi-correct format, making partial marking impossible. This means accuracy — not just knowledge — is essential for this topic.
What is the Arrhenius equation and why is it important for JEE Advanced?
The Arrhenius equation, k = Ae^(−Ea/RT), connects the rate constant k to temperature T and activation energy Ea. It is important for JEE Advanced because questions regularly ask you to interpret its graph, calculate Ea using two temperatures, or link it to equilibrium constants using ΔG° = −RT ln Keq.
How do you determine the order of a reaction from JEE Advanced data?
Use the ratio method: Rate₂/Rate₁ = ([A]₂/[A]₁)ⁿ. If the rate doubles when concentration doubles, n = 1; if it quadruples, n = 2; if it increases 8 times, n = 3. Also check half-life: if t₁/₂ is constant regardless of initial concentration, the reaction is first-order.
What is the difference between zero-order and first-order reactions in JEE questions?
In zero-order reactions, the rate is constant and [A] decreases linearly with time; t₁/₂ depends on initial concentration. In first-order reactions, [A] decreases exponentially; t₁/₂ = ln2/k is constant and independent of [A]₀. JEE Advanced 2010 tested both concepts in separate questions — so know both cold.
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How should I use JEE Advanced PYQs to improve my score in Chemical Kinetics?
First, solve the question independently without looking at the solution. Then check your method against the solution provided. If wrong, identify whether the error was conceptual (revisit theory) or computational (practise similar numerical drills). eSaral's 5-layer doubt-solving system — available on the app — lets you get step-by-step help from IIT Bombay faculty within minutes of getting stuck.