Chemical Kinetics – JEE Main Previous Year Questions with Solutions

JEE Main Previous Year Papers Questions of Chemistry with Solutions are available at eSaral. Practicing JEE Mains chapter wise questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas.

Simulator

Previous Years AIEEE/JEE Mains Questions

Q. The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log 2 = 0.301) :-

(1) 46.06 minutes             (2) 460.6 minutes            (3) 230.3 minutes              (4) 23.03 minutes

[aieee-2009]

Sol. (1)

Q. The time for half life period of a certain reaction A Products is 1 hour, when the initial concentration of the reactant ‘A’ is 2.0 mol L–1, How much time does it take for its concentration to come from 0.50 to 0.25 mol L–1 if it is a zero order reaction?

(1) 1 h

(2) 4 h

(3) 0.5 h

(4) 0.29.

[aieee-2010]

Sol. (4)

For zero order reaction

Q. Consider the reaction:

$\mathrm{Cl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{S}(\mathrm{aq}) \rightarrow \mathrm{S}(\mathrm{s})+2 \mathrm{H}^{+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq})$

The rate equation for this reaction is rate = $\mathrm{k}\left[\mathrm{Cl}_{2}\right]\left[\mathrm{H}_{2} \mathrm{S}\right]$

Which of these mechanisms is/are consistent with this rate equation?

[aieee-2010]

Sol. (1)

Q. A reactant (A) forms two products :

(1) $\mathrm{k}_{1}=2 \mathrm{k}_{2} \mathrm{e}^{\mathrm{E}_{2} / \mathrm{RT}}$

(2) $\mathrm{k}_{1}=\mathrm{k}_{2} \mathrm{e}^{\mathrm{Ea}_{1} / \mathrm{RT}}$

(3) $\mathrm{k}_{2}=\mathrm{k}_{1} \mathrm{e}^{\mathrm{Ea}_{2} / \mathrm{RT}}$

(4) $\mathrm{k}_{1}=\mathrm{A} \mathrm{k}_{2} \mathrm{e}^{\mathrm{Ea}_{1} / \mathrm{RT}}$

[aieee-2011]

Sol. (2)

Q. The rate of a chemical reaction doubles for every $10^{\circ} \mathrm{C}$ rise of temperature. If the temperature is raised by $50^{\circ} \mathrm{C}, \mathrm$ the rate of the reaction increases by about :-

(1) 32 times            (2) 64 times             (3) 10 times             (4) 24 times

[aieee-2011]

Sol. (1)

$\mathrm{k}_{2}=\mathrm{k}_{1}(2)^{5}=32 \mathrm{k}_{1}$

Q. For a first order reaction, (A)  products, the concentration of A changes from 0.1M to 0.025M in 40 minutes. The rate of reaction when the concentration of A is 0.01 M is :

(1) $1.73 \times 10^{-4} \mathrm{M} / \mathrm{min}$

(2) $1.73 \times 10^{-5} \mathrm{M} / \mathrm{min}$

(3) $3.47 \times 10^{-4} \mathrm{M} / \mathrm{min}$

(4) $3.47 \times 10^{-5} \mathrm{M} / \mathrm{m}$

[aieee-2012]

Sol. (3)

Q. The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be

$\left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{mol}^{-1} \text { and } \log 2=0.301\right)$

(1) $53.6 \mathrm{kJ} \mathrm{mol}^{-1}$

(2) $48.6 \mathrm{kJ} \mathrm{mol}^{-1}$

(3) $58.5 \mathrm{kJ} \mathrm{mol}^{-1}$

(4) $60.5 \mathrm{kJ} \mathrm{mol}^{-1}$

[J-main 2013]

Sol. (1)

Q. For the non-stoichiometre reaction 2A + B C + D, the following kinetic data were obtained in three separate experiments, all at 298 K.

(1) $\frac{\mathrm{dc}}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}][\mathrm{B}]^{2}$

(2) $\frac{\mathrm{dc}}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}]$

(3) $\frac{\mathrm{dc}}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}][\mathrm{B}]$

(4) $\frac{\mathrm{dc}}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}]^{2}[\mathrm{B}]$

[J-main 2014]

Sol. (2)

Q. Higher order (>3) reactions are rare due to :-

(1) shifting of equilibrium towards reactants due to elastic collision

(2) loss of active species on collision

(3) low probability of simultaneous collision of all the reacting species

(4) increase in entropy and activation energy as more molecules are involved.

[JEE-MAIN-(Offline) 2015]

Sol. (3)

Higher order (>3) reaction are rare due to low probability of simulatneous collision of more than three molecuels.

Q. The reaction

$2 \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g})$

follows first order kinetics. The pressure of a vessel containing only $\mathrm{N}_{2} \mathrm{O}_{5}$ was found to increase from 50 mm Hg to 87.5 mm Hg in 30 min. The pressure exerted by the gases after 60 min. will be (Assume temperature remains constant)

(1) 106.25 nm Hg

(2) 116.25 nm Hg

(3) 125 mm Hg

(4) 150 mm Hg

[JEE-MAIN (Online)2015]

Sol. (2)

Q. For the equilibrium, $\mathrm{A}(\mathrm{g}) \square \mathrm{B}(\mathrm{g}), \Delta \mathrm{H}$ is is –40 kJ/mol. If the ratio of the activation energies of the forward $\left(\mathrm{E}_{\mathrm{f}}\right)$ and reverse $\left(\mathrm{E}_{\mathrm{b}}\right)$ reactions is $\frac{2}{3}$ then :-

(1) $\mathrm{E}_{\mathrm{f}}=60 \mathrm{kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=100 \mathrm{kJ} / \mathrm{mol}$

$|(2) \mathrm{E}_{\mathrm{f}}=30 \mathrm{kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=70 \mathrm{kJ} / \mathrm{mol}$

(3) $\mathrm{E}_{\mathrm{f}}=80 \mathrm{kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=120 \mathrm{kJ} / \mathrm{mol}$

(4) $\mathrm{E}_{\mathrm{f}}=70 \mathrm{kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=30 \mathrm{kJ} / \mathrm{mol}$

[JEE-MAIN (Online)2015]

Sol. (3)

Q. Decomposition of $\mathrm{H}_{2} \mathrm{O}_{2}$ follows a first order reaction. In fifty minutes the concentration of $\mathrm{H}_{2} \mathrm{O}_{2}$ decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of $\mathrm{H}_{2} \mathrm{O}_{2}$ reaches 0.05 M, the rate of formation of $\mathrm{O}_{2}$ will be :-

[JEE – Main 2016]

Sol. (3)

$\mathrm{H}_{2} \mathrm{O}_{2(\mathrm{aq})} \longrightarrow \mathrm{H}_{2} \mathrm{O}_{(\mathrm{aq})}+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g})$

Q. Two reactions R1 and R2 have identical pre-exponential factors. Activation energy of $\mathrm{R}_{1}$ exceeds that of $\mathrm{R}_{2}$ by 10 kJ $\mathrm{mol}^{-1}$. If k1 and k2 are rate constants for reactions $\mathrm{R}_{1}$ and $\mathrm{R}_{2}$ respectively at 300 K, then ln $\left(\mathrm{k}_{2} / \mathrm{k}_{1}\right)$ is equal to :-

(1) 8 (2) 12 (3) 6 (4) 4

[JEE – Main 2017]

Sol. (4)

From arrhenius equation,

Q. At $518^{\circ} \mathrm{C}$, the rate of decomposition of a sample of gaseous acetaldehyde, initially at a pressure of 363 Torr, was 1.00 Torr $\mathrm{s}^{-1}$ when 5% had reacted and 0.5 Torr s–1 when 33% had reacted. The order of the reaction is :

(1)3

(2) 1

(3) 0

(4) 2

[JEE – Main 2018]

Sol. (4)

• May 22, 2020 at 4:17 pm

Chill bro

• May 18, 2020 at 9:20 pm

Best content and methods of explanation questions are easy I solved all very easily

• May 18, 2020 at 3:46 pm

awesome problems thanks for the support but make the notes and solution more easy and complete some solutions

• May 17, 2020 at 1:45 pm

halwa q

• April 23, 2020 at 8:38 pm

Very good problems to do here and explanations are very good. I can understand the problems very easily.

• April 23, 2020 at 6:55 pm

Very good explanation

• April 4, 2020 at 9:27 pm

very easy paper

• March 29, 2020 at 12:11 pm

Good explanation

• March 26, 2020 at 1:54 pm

Very good explanation