Hey, students are you looking for Comparing quantities class 8 formulas? If yes. Then you are at the right place.
In this post, I have listed all the formulas of Comparing quantities class 8 that you can use to learn and understand the concepts easily.
If you want to improve your class 8 Math, Comparing quantities concepts, then it is super important for you to learn and understand all the formulas.
By using these formulas you will learn about Comparing quantities.
With the help of these formulas, you can revise the entire chapter easily.
Simple Interest(SI):
When the interest is paid to the lender regularly every year or half year on the same interest, we call it a simple interest. In other words, interest is said to simple, if it is calculated on the original principle throughout the loan period.
$S . I .=\frac{P \times R \times T}{100}$
Where, $\mathrm{P}=$ Principal, $\mathrm{R}=$ Rate of Interest, $\mathrm{T}=$ Time .
Compound Interest (CI):
If the borrower and the lender agree to fix up a certain interval of time (say, a year or a half-year or a quarter of a year, etc.), so that the amount at the end of an interval becomes the principal for the next-interval, then the total interest over all the intervals calculated in this way is called the compound interest. Also, CI = Amount – Principal
(a) When interest is compounded annually, then
Amount $A=P\left(1+\frac{R}{100}\right)^{n}$ and $\mathrm{CI}=\mathrm{A}-\mathrm{P}=\mathrm{P}\left\{\left(1+\frac{\mathrm{R}}{100}\right)^{\mathrm{n}}-1\right\}$
where P is Principal, R is the rate of interest and n is time period.
(b) When Interest is Compounded Half-Yearly, then
Amount $A=P\left(1+\frac{R}{2 \times 100}\right)^{2 n}$
where $\left\{\begin{array}{l}\frac{\mathrm{R}}{2} \text { is half yearly rate and } \\ 2 n=\text { number of half-years }\end{array}\right.$
and $C I=A-P=P\left\{\left(1+\frac{R}{2 \times 100}\right)^{2 n}-1\right\}$
When R1, R2 and R3 are different rates for the first, second and third year, then
Amount $A=P\left(1+\frac{R_{1}}{100}\right)\left(1+\frac{R_{2}}{100}\right)\left(1+\frac{R_{3}}{100}\right)$
and $C I=A-P=P\left\{\left(1+\frac{R_{1}}{100}\right)\left(1+\frac{R_{2}}{100}\right)\left(1+\frac{R_{3}}{100}\right)-1\right\}$
Also Read,
Download NCERT Class 8 Maths Book in PDF
Download NCERT Class 8 Science Book in PDF
Download NCERT Class 8 Science Exemplar in PDF
Download NCERT Class 8 Maths Exemplar in PDF
If you have any Confusion related to Comparing quantities Class 8 Maths Formulas, then feel free to ask in the comments section down below.
To watch Free Learning Videos on Class 8 Maths by Kota’s top Faculties Install the eSaral App
If you want to improve your class 8 Math, Comparing quantities concepts, then it is super important for you to learn and understand all the formulas.
By using these formulas you will learn about Comparing quantities.
With the help of these formulas, you can revise the entire chapter easily.
Comparing quantities class 8 formulas
- The discount is a reduction given on the market price. Discount = Marked Price – Selling price.
- The discount can be calculated when the discount percentage is given. Discount = Discount % of marked Price.
- Additional expenses made after buying an article are included in the cost price and are known as overhead expenses. C.P = Buying Price + Overhead expenses
- Sales tax is charged on the sale of an item by the government and is added to the bill amount. Sales tax = Tax % of the bill amount
- Sales Tax $=\frac{\text { C.P. } \times \text { Rate of S.T. }}{100}$
where
M.P. = Marked Price
S.P. = Selling Price
M.P = S.E + Discount
Discount = M.P – S.P - Discount $\%=\frac{\text { Discount } \times 100}{\text { M.P. }}$
- When profit % is given, then S.P > C.P and
S.P. $=\left(\frac{100+\text { Profit } \%}{100}\right) \times$ C.P
C.P. $=\frac{\text { S.P. } \times 100}{100+\text { Profit } \%}$
Profit $=\frac{\text { Profit } \% \times \text { C.P. }}{100}$
Profit (gain) $=$ S.P. $-$ C.P.
Profit $\%=\frac{\text { Profit }}{\text { C.P. }} \times 100$ - When loss % is given S.P < C.P and
S.P. $=\frac{100-\text { Loss } \%}{100} \times$ C.P.
C.P. $=\frac{\text { S.P. } \times 100}{100-\text { Loss } \%}$
Loss $=\frac{\text { Loss } \% \times \text { C.P. }}{100}$
Loss $=$ C.P. $-$ S.P.
Loss $\%=\frac{\text { Loss }}{\text { C.P. }} \times 100$ - Increase and Decrease Percent
Increase $\%=\left(\frac{\text { Increase }}{\text { Original value }} \times 100\right) \%$
Decrease $\%=\left(\frac{\text { Decrease }}{\text { Original value }} \times 100\right) \%$
Simple Interest(SI):
When the interest is paid to the lender regularly every year or half year on the same interest, we call it a simple interest. In other words, interest is said to simple, if it is calculated on the original principle throughout the loan period.
$S . I .=\frac{P \times R \times T}{100}$
Where, $\mathrm{P}=$ Principal, $\mathrm{R}=$ Rate of Interest, $\mathrm{T}=$ Time .
Compound Interest (CI):
If the borrower and the lender agree to fix up a certain interval of time (say, a year or a half-year or a quarter of a year, etc.), so that the amount at the end of an interval becomes the principal for the next-interval, then the total interest over all the intervals calculated in this way is called the compound interest. Also, CI = Amount – Principal
(a) When interest is compounded annually, then
Amount $A=P\left(1+\frac{R}{100}\right)^{n}$ and $\mathrm{CI}=\mathrm{A}-\mathrm{P}=\mathrm{P}\left\{\left(1+\frac{\mathrm{R}}{100}\right)^{\mathrm{n}}-1\right\}$
where P is Principal, R is the rate of interest and n is time period.
(b) When Interest is Compounded Half-Yearly, then
Amount $A=P\left(1+\frac{R}{2 \times 100}\right)^{2 n}$
where $\left\{\begin{array}{l}\frac{\mathrm{R}}{2} \text { is half yearly rate and } \\ 2 n=\text { number of half-years }\end{array}\right.$
and $C I=A-P=P\left\{\left(1+\frac{R}{2 \times 100}\right)^{2 n}-1\right\}$
When R1, R2 and R3 are different rates for the first, second and third year, then
Amount $A=P\left(1+\frac{R_{1}}{100}\right)\left(1+\frac{R_{2}}{100}\right)\left(1+\frac{R_{3}}{100}\right)$
and $C I=A-P=P\left\{\left(1+\frac{R_{1}}{100}\right)\left(1+\frac{R_{2}}{100}\right)\left(1+\frac{R_{3}}{100}\right)-1\right\}$
Also Read,
Download NCERT Class 8 Maths Book in PDF
Download NCERT Class 8 Science Book in PDF
Download NCERT Class 8 Science Exemplar in PDF
Download NCERT Class 8 Maths Exemplar in PDF
If you have any Confusion related to Comparing quantities Class 8 Maths Formulas, then feel free to ask in the comments section down below.
To watch Free Learning Videos on Class 8 Maths by Kota’s top Faculties Install the eSaral App