Compound Angle – JEE Advanced Previous Year Questions with Solutions

Download India's Best Exam Preparation App

Class 9-10, JEE & NEET

Download eSaral App
JEE Advanced Previous Year Questions of Math with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of mathematics will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. eSaral helps the students in clearing and understanding each topic in a better way. eSaral also provides complete chapter-wise notes of Class 11th and 12th both for all subjects. Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more. Download eSaral app for free study material and video tutorials. Simulator Previous Years JEE Advance Questions One or more than one is/are correct : [Q.1(a) & (b)]
Q. If $\frac{\sin ^{4} x}{2}+\frac{\cos ^{4} x}{3}=\frac{1}{5},$ then (A) $\tan ^{2} x=\frac{2}{3}$ (B) $\frac{\sin ^{8} x}{8}+\frac{\cos ^{8} x}{27}=\frac{1}{125}$ (C) $\tan ^{2} \mathrm{x}=\frac{1}{3}$ (D) $\frac{\sin ^{8} x}{8}+\frac{\cos ^{8} x}{27}=\frac{2}{125}$ [JEE 2009, 4 + 4]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (A,B) (a) $\frac{\tan ^{4} x}{2}+\frac{1}{3}=\frac{\sec ^{4} x}{5}$ put $\tan ^{2} \mathrm{x}=\mathrm{t}$ on solving we get $t=2 / 3$ $\Rightarrow \sin ^{2} x=\frac{2}{5} \quad \Rightarrow \quad \cos ^{2} x=\frac{3}{5}$

Q. For $0<\theta<\frac{\pi}{2},$ the solution(s) of $\sum_{m=1}^{6} \csc \left(\theta+\frac{(m-1) \pi}{4}\right) \csc \left(\theta+\frac{m \pi}{4}\right)=4 \sqrt{2}$ is (are) (A) $\frac{\pi}{4}$ (B) $\frac{\pi}{6}$ (C) $\frac{\pi}{12}$ (D) $\frac{5 \pi}{12}$ [JEE 2009, 4 + 4]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (C,D)

Q. The maximum value of the expression $\frac{1}{\sin ^{2} \theta+3 \sin \theta \cos \theta+5 \cos ^{2} \theta}$ is [JEE 2010,3+3]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. 2

Q. Two parallel chords of a circle of radius 2 are at a distance $\sqrt{3}+1$ apart. If the chords subtend at the center, angles of $\frac{\pi}{k}$ and $\frac{2 \pi}{k}$ where $\mathrm{k}>0$, Glue of $[\mathrm{k}]$ is – [JEE 2010,3+3]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. k=3

Q. Let $\mathrm{P}=\{\theta: \sin \theta-\cos \theta=\sqrt{2} \cos \theta\}$ and $\mathrm{Q}=\{\theta: \sin \theta+\cos \theta=\sqrt{2} \sin \theta\}$ be two sets. Then [JEE 2011,3]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (D)

Q. The value of $\sum_{\mathrm{k}=1}^{13} \frac{1}{\sin \left(\frac{\pi}{4}+\frac{(\mathrm{k}-1) \pi}{6}\right) \sin \left(\frac{\pi}{4}+\frac{\mathrm{k} \pi}{6}\right)}$ is equal to (A) $3-\sqrt{3}$ (B) $2(3-\sqrt{3})$ (C) $2(\sqrt{3}-1)$ (D) $2(2+\sqrt{3})$ [JEE Advance 2016]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (C)

Q. Let $\alpha$ and $\beta$ be nonzero real numbers such that $2(\cos \beta-\cos \alpha)+\cos \alpha \cos \beta=1$. Then which of the following is/are true ? (A) $\tan \left(\frac{\alpha}{2}\right)-\sqrt{3} \tan \left(\frac{\beta}{2}\right)=0$ (B) $\sqrt{3} \tan \left(\frac{\alpha}{2}\right)-\tan \left(\frac{\beta}{2}\right)=0$ (C) $\tan \left(\frac{\alpha}{2}\right)+\sqrt{3} \tan \left(\frac{\beta}{2}\right)=0$ (D) $\sqrt{3} \tan \left(\frac{\alpha}{2}\right)+\tan \left(\frac{\beta}{2}\right)=0$ [JEE Advance 2017]

Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...

Sol. (A,C)

   
Administrator

Leave a comment

Please enter comment.
Please enter your name.