Compound Angle – JEE Main Previous Year Question with Solutions
JEE Main Previous Year Question of Math with Solutions are available at eSaral. Practicing JEE Main Previous Year Papers Questions of mathematics will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas.Get detailed Class 11th &12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc.eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects.Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more.Download eSaral app for free study material and video tutorials.SimulatorPrevious Years AIEEE/JEE Mains Questions
Q. Let $\cos (\alpha+\beta)=\frac{4}{5}$ and $\operatorname{let} \sin (\alpha-\beta)=\frac{5}{13},$ where $0 \leq \alpha, \beta \leq \frac{\pi}{4} .$ Then $\tan 2 \alpha=$(1) $\frac{25}{16}$(2) $\frac{56}{33}$(3) $\frac{19}{12}$(3) $\frac{19}{12}$ [AIEEE-2010]

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Sol. (2)

Q. If $\mathrm{A}=\sin ^{2} \mathrm{x}+\cos ^{4} \mathrm{x},$ then for all real $\mathrm{x}:-$(1) $1 \leq \mathrm{A} \leq 2$(2) $\frac{3}{4} \leq \mathrm{A} \leq \frac{13}{16}$(3) $\frac{3}{4} \leq \mathrm{A} \leq 1$(4) $\frac{13}{16} \leq \mathrm{A} \leq 1$ [AIEEE-2011]

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Sol. (3)

Q. In a $\Delta \mathrm{PQR},$ if $3 \sin \mathrm{P}+4 \cos \mathrm{Q}=6$ and $4 \sin \mathrm{Q}+3 \cos \mathrm{P}=1,$ then the angle $\mathrm{R}$ is equal to:(1) $\frac{3 \pi}{4}$(2) $\frac{5 \pi}{6}$(3) $\frac{\pi}{6}$(4) $\frac{\pi}{4}$ [AIEEE-2012]

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Sol. (3)

Q. The expression $\frac{\tan \mathrm{A}}{1-\cot \mathrm{A}}+\frac{\cot \mathrm{A}}{1-\tan \mathrm{A}}$ can be written as(1) sinA cosA + 1(2) secA cosecA + 1(3) tanA + cotA(4) secA + cosecA [JEE-MAIN 2013]

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Sol. (2)

Q. $\mathrm{ABCD}$ is a trapezium such that $\mathrm{AB}$ and $\mathrm{CD}$ are parallel and $\mathrm{BC} \perp \mathrm{CD} .$ If $\angle \mathrm{ADB}=\theta, \mathrm{BC}$$=\mathrm{p} and \mathrm{CD}=\mathrm{q}, then \mathrm{AB} is equal to(1) \frac{\left(\mathrm{p}^{2}+\mathrm{q}^{2}\right) \sin \theta}{\mathrm{p} \cos \theta+\mathrm{q} \sin \theta}(2) \frac{\mathrm{p}^{2}+\mathrm{q}^{2} \cos \theta}{\mathrm{p} \cos \theta+\mathrm{q} \sin \theta}(3) \frac{\mathrm{p}^{2}+\mathrm{q}^{2}}{\mathrm{p}^{2} \cos \theta+\mathrm{q}^{2} \sin \theta}(4) \frac{\left(p^{2}+q^{2}\right) \sin \theta}{(p \cos \theta+q \sin \theta)^{2}} [JEE-MAIN 2013] Download eSaral App for Video Lectures, Complete Revision, Study Material and much more... Sol. (1) Q. Let \mathrm{f}_{\mathrm{K}}(\mathrm{x})=\frac{1}{\mathrm{k}}\left(\sin ^{\mathrm{k}} \mathrm{x}+\cos ^{\mathrm{k}} \mathrm{x}\right) where \mathrm{x} \in \mathrm{R} and \mathrm{k} \geq 1 . Then \mathrm{f}_{4}(\mathrm{x})-\mathrm{f}_{6}(\mathrm{x}) equals :(1) \frac{1}{6}(2) \frac{1}{3}(3) \frac{1}{4}(4) \frac{1}{12} [JEE-MAIN 2014] Download eSaral App for Video Lectures, Complete Revision, Study Material and much more... Sol. (4) Q. If 5\left(\tan ^{2} x-\cos ^{2} x\right)=2 \cos 2 x+9, then the value of \cos 4 x is :-(1)-\frac{7}{9}$$(2)-\frac{3}{5}$(3) $\frac{1}{3}$(4) $\frac{2}{9}$ [JEE-MAIN 2017]

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Sol. (1)

• December 1, 2021 at 1:05 pm

nice questions

• June 6, 2021 at 10:11 am

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• August 14, 2020 at 12:37 pm

Thank you. These were very helpful.

• July 3, 2020 at 9:06 am

Nice questions
Make some more difficult
Nice..

• July 30, 2021 at 3:46 pm

Hm

• June 20, 2020 at 4:18 pm

You can have aa better explanation ….

• May 22, 2020 at 7:38 am

Chill bro

• April 7, 2020 at 12:56 pm

nice perfomance from you i loved your work we students who are preparing for furture exams must need it a lot thank you so much

• March 23, 2020 at 12:40 pm

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• July 16, 2022 at 5:26 pm

Nice 👍..