## Cyclotron Frequency

Under the action of the given magnetic field (B fixed), the given positive ion (e/m fixed) will cover the semi-circular path in a fixed time only, if t in equation is equal to $\frac{T}{2}$ Where T is the time period of the electric field.

### Maximum energy of the positive ions

Maximum energy acquired by positive ions depends on the radius R of the dees. After acquire this energy positive ion emerge out the dees and use for hitting the target. Let $\mathrm{V}_{\mathrm{max}}$ be the velocity acquired by the positive ions, when it moves along the largest circular path i.e. path of radius equal to the radius R of the dees. Then $\mathrm{B} \mathrm{q} \mathrm{v}_{\max }=\frac{\mathrm{m} \mathrm{v}_{\max }^{2}}{\mathrm{R}}$**OR**$v_{\max }=\frac{B q R}{m}$ Therefore maximum kinetic energy gained by the positive ion, $$ E_{\max }=\frac{1}{2} m v_{\max }^{2}=\frac{1}{2} m\left(\frac{B q R}{m}\right)^{2} $$

**OR**$E_{\max }=\frac{1}{2} \frac{B^{2} q^{2} R^{2}}{m}$ The maximum energy acquired by the positive ion can be expressed in another form as given below : If V is the potential difference applied between the dees and N is the number of times, the positive ion cross the gap between the dees before leaving the dees, then $E_{\max }=N q V$ $N=2 n$ $n=$ the number of rotations completede. Also Read:

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In this cylotronas components name that andexplanation of that