**Simulator**

**Previous Years AIEEE/JEE Mains Questions**

Q. If a source of power $4 \mathrm{kW}$ produces $10^{20}$ photons/second, the radiation belongs to a part of the spectrum called
(1) microwaves
(2) y-rays
(3) X-rays
(4) ultraviolet rays

**[AIEEEE 2010]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(3) Power $=\frac{\text { nhc }}{\lambda} \lambda \approx 1 \mathrm{A} \equiv \mathrm{X}$ Rays

Q. An electromagnetic wave in vacuum has the electric and magnetic fields $\overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{B}}$, which are
always perpendicular to each other. The direction of polarization is given by $\overrightarrow{\mathrm{X}}$ and that ofwave
propagation by $\overrightarrow{\mathrm{k}}$. Then
(1) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{B}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$
(2) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{E}}$
(3) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{B}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{E}}$
(4) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$

**AIEEE-2012**
Q. Match List-I (Electromagnetic wave type) with List-II (Its association/application) and select the correct option from the choices given below the lists:

**[JEE- Mains 2014]**
Q. During the propagation of electromagnetic waves in a medium:
(1) Electric energy density is equal to the magnetic energy density
(2) Both electric magnetic energy densities are zero
(3) Electric energy density is double of the magnetic energy density
(4) Electric energy density is half of the magnetic energy density.

**[JEE- Mains 2014]**
Q. A red LED emits light at 0.1 watt uniformly around it. The amplitude of the electric field of the light at a distance of 1 $\mathrm{m}$ from the diode is :-
(1) $5.48 \mathrm{V} / \mathrm{m}$
(2) $7.75 \mathrm{V} / \mathrm{m}$
(3) $1.73 \mathrm{V} / \mathrm{m}$
(4) $2.45 \mathrm{V} / \mathrm{m}$

**[JEE- Mains 2015]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(4) $\mathrm{I}_{\mathrm{av}}=\frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{C}=\frac{\mathrm{P}}{4 \pi \mathrm{r}^{2}}$ $\mathrm{E}=\sqrt{\frac{2 \mathrm{P}}{4 \pi \mathrm{r}^{2} \varepsilon_{0} \mathrm{c}}}$ On putting value we get $=2.45 \mathrm{v} / \mathrm{m} .$

Q. Arrange the following electromagnetic radiations per quantum in the order of increasing energy :-

**[JEE- Mains 2016]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(2) Energy $=\frac{\mathrm{hc}}{\lambda}$ order of wavelength $x$ ray, VIBGYOR, Radiowaves

Isme to latest question nhi h sir ……

Not enough questions in this auch a stupid and worst app ….

More concept solutions required

Great

More problems required

Not so useful and better add more problems

Not enough question

Bsdk aur questions Dal randi

loll

Madarchod website. Chutiye developer, baki saare questions kaha gaye?

Should have added more questions…

That’s a good one