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**Simulator**

**Previous Years AIEEE/JEE Mains Questions**

(1) microwaves

(2) y-rays

(3) X-rays

(4) ultraviolet rays

**[AIEEEE 2010]**

**Sol.**(3)

Power $=\frac{\text { nhc }}{\lambda} \lambda \approx 1 \mathrm{A} \equiv \mathrm{X}$ Rays

always perpendicular to each other. The direction of polarization is given by $\overrightarrow{\mathrm{X}}$ and that ofwave

propagation by $\overrightarrow{\mathrm{k}}$. Then

(1) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{B}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$

(2) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{E}}$

(3) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{B}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{E}}$

(4) $\overrightarrow{\mathrm{X}} \| \overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{k}} \| \overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$

**AIEEE-2012**

**Sol.**(4)

**[JEE- Mains 2014]**

**Sol.**(2)

(1) Electric energy density is equal to the magnetic energy density

(2) Both electric magnetic energy densities are zero

(3) Electric energy density is double of the magnetic energy density

(4) Electric energy density is half of the magnetic energy density.

**[JEE- Mains 2014]**

**Sol.**(1)

(1) $5.48 \mathrm{V} / \mathrm{m}$

(2) $7.75 \mathrm{V} / \mathrm{m}$

(3) $1.73 \mathrm{V} / \mathrm{m}$

(4) $2.45 \mathrm{V} / \mathrm{m}$

**[JEE- Mains 2015]**

**Sol.**(4)

$\mathrm{I}_{\mathrm{av}}=\frac{1}{2} \varepsilon_{0} \mathrm{E}^{2} \mathrm{C}=\frac{\mathrm{P}}{4 \pi \mathrm{r}^{2}}$

$\mathrm{E}=\sqrt{\frac{2 \mathrm{P}}{4 \pi \mathrm{r}^{2} \varepsilon_{0} \mathrm{c}}}$

On putting value we get

$=2.45 \mathrm{v} / \mathrm{m} .$

**[JEE- Mains 2016]**

**Sol.**(2)

Energy $=\frac{\mathrm{hc}}{\lambda}$

order of wavelength

$x$ ray, VIBGYOR, Radiowaves