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$\mathrm{p}$ and $\mathrm{CD}=\mathrm{q},$ then $\mathrm{AB}$ is equal to

(1) $\frac{\left(p^{2}+q^{2}\right) \sin \theta}{p \cos \theta+q \sin \theta}$

(2) $\frac{p^{2}+q^{2} \cos \theta}{p \cos \theta+q \sin \theta}$

(3) $\frac{p^{2}+q^{2}}{p^{2} \cos \theta+q^{2} \sin \theta}$

(4) $\frac{\left(p^{2}+q^{2}\right) \sin \theta}{(p \cos \theta+q \sin \theta)^{2}}$

**[JEE-MAINS-2013]**

**Sol.**(1)

(1) $1: \sqrt{3}$

(2) 2 : 3

(3) $\sqrt{3}: 1$

(4) $\sqrt{3}: \sqrt{2}$

**[JEE(Main)-2015]**

**Sol.**(3)

(1) 5 (2) 6 (3) 10 (4) 20

**[JEE(Main)-2016]**

**Sol.**(1)

(1) $\frac{4}{9}$

(2) $\frac{6}{7}$

(3) $\frac{1}{4}$

(4) $\frac{2}{9}$

**[JEE(Main)-2017]**

**Sol.**(4)

(1) 50

(2) $100 \sqrt{3}$

(3) $50 \sqrt{2}$

(4) 100

**[JEE(Main)-2018]**

**Sol.**(4)

sir this esaral is providing a very gud set of questions…

but its need to update a little, we the students are ariving 2020 jee and for that we need latest jee online questions.

these questions are just incomplete

sir this esaral is providing a very gud set of questions…

but its need to update a little, we the students are ariving 2020 jee and for that we need latest jee online questions.

Chill bro

Nice but try to update

Now 2020 but questions are up to 2018