Ionic Equilibrium- JEE Advanced Previous Year Questions with Solutions
JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. Simulator Previous Years JEE Advance Questions
Q. The dissociation constant of a substituted benzoic acid at $25^{\circ} \mathrm{C}$ is $1.0 \times 10^{-4}$ . The pH of a 0.01 M solution of its sodium salt is [JEE 2009]

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Sol. 8$\mathrm{K}_{\mathrm{h}}=\frac{\mathrm{K}_{\mathrm{w}}}{\mathrm{K}_{\mathrm{a}}}=\frac{10^{-14}}{10^{-4}}=10^{-10}$$\mathrm{h}=\sqrt{\frac{\mathrm{K}_{\mathrm{h}}}{\mathrm{C}_{0}}}=\sqrt{\frac{10^{-10}}{10^{-2}}}=10^{-4}$$\mathrm{pH}=\frac{1}{2}[\mathrm{pKw}+\mathrm{pKa}+\log \mathrm{Co}]$$\mathrm{pH}=\frac{1}{2}\left[14+4+\log 10^{-2}\right]$$\mathrm{pH}=\frac{1}{2}[16]=8$

Q. Aqueous solutions of $\mathrm{HNO}_{3}, \mathrm{KOH}, \mathrm{CH}_{3} \mathrm{COOH}$ and $\mathrm{CH}_{3} \mathrm{COONa}$ of identical concentrations are provided. The pair(s) of solutions which form a buffer upon mixing is(are)(A) $\mathrm{HNO}_{3}$ and $\mathrm{CH}_{3} \mathrm{COOH}$(B) $\mathrm{KOH}$ and $\mathrm{CH}_{3} \mathrm{COONa}$(C) $\mathrm{HNO}_{3}$ and $\mathrm{CH}_{3} \mathrm{COONa}$(D) $\mathrm{CH}_{3} \mathrm{COOH}$ and $\mathrm{CH}_{3} \mathrm{COONa}$

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Sol. (C,D)

Q. In 1 L saturated solution of AgCl $\left[\mathrm{K}_{\mathrm{sp}}(\mathrm{AgCl})=1.6 \times 10^{-10}\right], 0.1 \mathrm{mol}$ of $\mathrm{CuCl}$$\left[\mathrm{K}_{\mathrm{sp}}(\mathrm{CuCl})=1.0 \times 10^{-6}\right] is added.The resultant concentration of \mathrm{Ag}^{+} in the solution is 1.6 × 10^{-x}. The value of ‘x’ is. [JEE -2011] Download eSaral App for Video Lectures, Complete Revision, Study Material and much more... Sol. 7 Q. The initial rate of hydrolysis of methyl acetate (1M) by a weak acid (HA, 1M) is 1 / 100^{\text {th }} of that of a strong acid (HX, 1M), at 25^{\circ} \mathrm{C}. The \mathrm{K}_{\mathrm{a}} of HA is(A) 1 \times 10^{-4}(B) 1 \times 10^{-5}(C) 1 \times 10^{-6}(D) 1 \times 10^{-3} [JEE 2013] Download eSaral App for Video Lectures, Complete Revision, Study Material and much more... Sol. (A) Q. The \mathrm{K}_{\mathrm{sp}} of \mathrm{Ag}_{2} \mathrm{CrO}_{4} is 1.1 \times 10^{-12} at 298 K. The solubility (in mol/L) of \mathrm{Ag}_{2} \mathrm{CrO}_{4} in a 0.1 \mathrm{M} \mathrm{AgNO}_{3}solution is(A) 1.1 \times 10^{-11}(B) 1.1 \times 10^{-10}(C) 1.1 \times 10^{-12}(D) 1.1 \times 10^{-9} [JEE 2013] Download eSaral App for Video Lectures, Complete Revision, Study Material and much more... Sol. (B) Q. Dilution process of different aqueous solutions; with water, are given in LIST-I. Theeffects of dilution of the solutions on \left[\mathrm{H}^{+}\right] are given in LIST II.(Note : Degree of dissociation () of weak acid and weak base is << 1; degree of hydrolysis of salt <<1; \left[\mathrm{H}^{+}\right] represents the concentration of \mathrm{H}^{+} ions)Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is(\mathrm{A}) \mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 1(B) \mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 3(C) \mathrm{P} \rightarrow 1 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 3$$(\mathrm{D}) \mathrm{P} \rightarrow 1 ; \mathrm{Q} \rightarrow 5 ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow 1$ [JEE- Adv. – 2018]

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Sol. (D)correct match : Q-5

• April 23, 2022 at 8:23 pm

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• April 23, 2022 at 8:22 pm

Thanks

• August 15, 2020 at 7:41 pm

Nice questions
Make it some more difficult
Well
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• August 7, 2020 at 4:38 pm

it helped me,
thank you

• October 13, 2020 at 12:59 pm

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• March 31, 2020 at 12:19 am

Good content