NCERT Solutions for Class 10 Maths chapter 7 Exercise 7.1 Coordinate Geometry  PDF
Class 10NCERT has provided a solution for class 10 maths chapter 7 ex 7.1 Coordinate Geometry, which involves the application of a distance formula to determine the distance between points situated in the Cartesian plane. When solving the distance formula, we will only use the positive square root because the distance cannot be negative. All NCERT solutions of class 10, maths chapter 7, ex 7.1, are oneofakind, so students can use them to explore this concept.
Exercise 7.1 consists of 10 questions that are based on the distance formula. Most of the questions are based on real life situations. The questions presented in this exercise are relatively straightforward as they illustrate how the distance formula can be used directly in various ways.
Class 10 maths chapter 7 exercise 7.1 NCERT solutions is provided in PDF format to assist students in preparing for the exam. All questions provided in the exercise are included in the PDF. You can download a free PDF of these solutions to practice questions.
Topics Covered in Exercise 7.1 Class 10 Mathematics Questions
NCERT solutions class 10 maths chapter 7 ex 7.1 discussed distance formula, which is described below.
1. 
Distance Formula 

Distance Formula  The distance formula is a formula used to determine the distance between two points, provided that the coordinates are known. These coordinates may be located on the xaxis or on the yaxis, or on both.
Let's say we have two points, P and Q, in the XY plane. Coordinates of Point P are (x1, y1) and coordinates of point Q are (x2, y2). The formula for determining the distance between two PQs is as follows:
PQ = √[(x2 – x1)^2 + (y2 – y1)^2]
Or
D = √[(x2 – x1)^2 + (y2 – y1)^2] (Where ‘D’ is the distance between the points.)
In the same way, the distance of a point P(x, y) from the origin O(0, 0) is given by:
OP = √(x2 + y2)
Tips for Solving Exercise 7.1 Class 10 chapter 7 Coordinate Geometry
NCERT solutions class 10 maths chapter 7 exercise 7.1 Coordinate Geometry covers the distance formula. Our academic maths experts have been provided some essential tips to solve the ex 7.1 questions with ease.

NCERT solutions for Distance formula, as explained by eSaral subject experts, will help students to determine the distance between 2 points. The formula is derived from the Pythagorean theorem. All you need are coordinates ( x,y) and you can use this formula to determine the distance.

In this exercise, all the 10 questions are based on the concept of coordinates and formula for distance. Therefore, you must remember the distance formula to solve questions.

NCERT solutions class 10 maths chapter 7 ex 7.1 is based on the concept of visualizing the questions. Therefore, the students need to have a clear picture of the questions in order to be able to visualize them. With the help of this exercise, the students will gradually become familiar with the graphs that will be useful in further lesson.
Importance of Solving Ex 7.1 Class 10 Maths chapter 7 Coordinate Geometry
Solving NCERT solutions for ex 7.1 class 10 maths chapter 7 coordinate geometry gives you a lot of benefits. Here, you can go through these benefits provided below.

NCERT solutions for ex 7.1 class 10 will teach you how to calculate distance from a point, so you'll be wellversed in the concepts.

It gives you questions with different levels of difficulty for your practice.

The questions included in ex 7.1 are solved by expert teachers of eSaral.

By solving ex 7.1 chapter 7 will boost your confidence.
Frequently Asked Questions
Question 1. What is the distance between 2 points?
Answer 1. The length of a line segment that connects two points is known as the distance between the two points. Let's say you have two points, (x1,y1) and (x2,y2). The distance between these two points is √[(x2 – x1)^2 + (y2 – y1)^2].
Question 2. How to calculate the distance?
Answer 2. The formula for determining the distance is derived from the Pythagorean theorem. Distance formula in coordinate geometry is √[(x2 – x1)^2 + (y2 – y1)^2].
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