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# NCERT Solutions for Class 12 Maths Chapter 13 Exercise 13.1 Probability - PDF Download

NCERT solutions for class 12 maths chapter 13 exercise 13.1 Probability presents the thorough comprehension of conditional probability and its properties. By solving questions in ex 13.1 class 12 maths solutions, you will understand the importance of the properties of conditional probability and its implementation to the questions. In NCERT solutions for class 12 maths chapter 12 ex 13.1, eSaral’s subject matter experts have explained conditional probability and its properties with a simple approach. By studying with these solutions, you can not only solve the questions of ex 13.1 but also score good marks in board exams.

Ex 13.1 class 12 maths chapter 13 consists of 17 questions that apply the core fundamental concepts of conditional probability in the easiest way. By the thorough practice of questions provided in class 12 maths chapter 13 exercise 13.1 NCERT solutions, you can erase the mistakes and confusions. Ex 13.1 class 12 maths ch 13 is also developed in PDF format at eSaral. You can download the free PDF of these NCERT solutions from the eSaral website and practice all the questions of ex 13.1 anytime. The link to download the PDF for ex 13.1 class 12 maths is given below.

## Topics Covered in Exercise 13.1 Class 12 Mathematics Questions

NCERT solutions for class 12 maths chapter 13 ex 13.1 talks about conditional probability and properties of conditional probability.

 1 Conditional Probability Properties of conditional probability
1. Conditional Probability

If E and F are two events associated with the same sample space of a random experiment, the conditional probability of the event E given that F has occurred, i.e. P (E|F) is given by

$P(E \mid F)=\frac{P(E \cap F)}{P(F)}$ provided $P(F) \neq 0$

• Properties of conditional probability

Property 1 P(S|F) = P(F|F) = 1

Property 2 If A and B are any two events of a sample space S and F is an event of S such that P(F) ≠ 0, then

P((A ∪ B)|F) = P(A|F) + P(B|F) – P((A ∩ B)|F)

Property 3 P(E′|F) = 1 − P(E|F)

## Tips for Solving Exercise 13.1 Class 12 Chapter 13 Probability

Our expert faculty of mathematics have provided some very useful tips for solving questions of ex 13.1 class 12 maths chapter 13 Probability.

1. Conditional probability questions require practice rather than learning theory so you must solve questions related to conditional probability as much as you can.

2. There are significant properties of conditional probability that must be comprehended before solving exercise questions.

3. You should start solving simple questions first and then move to the complex ones with stepwise solutions that will build understanding of each concept.

4. There are few examples before ex 13.1 that you must solve for better understanding of the topic.

## Importance of Solving Ex 13.1 Class 12 Maths Chapter 13 Probability

There are numerous benefits of solving ex 13.1 class 12 maths chapter 13. Here, eSaral’s experts of mathematics have combined a few of them for your convenience.

1. The topic of conditional probability and its properties in NCERT solution for ex 13.1 class 12 maths chapter 13 have been elaborated by experienced teachers of eSaral that helps you to understand the concepts while solving problems.

2. Each question in ex 13.1 class 12 maths solutions are solved with stepwise methods and properties are explained in simple language for clear understanding of questions.

3. Solving questions with the help of NCERT solution PDF for class 12 maths chapter 13 ex 13.1 will provide you accurate answers for all questions that will boost your self-confidence.

4. By consistent practice of questions included in exercise 13.1 will help you strengthen your problem solving skills.

Question 1. What is the conditional probability?

Answer 1. Conditional probability is defined as the likelihood of an event occurring based on the occurrence of a previous event.

Question 2. Write the formula for conditional probability?

Answer 2. The conditional probability of an event E, given the occurrence of the event F is given by:

$P(E \mid F)=\frac{P(E \cap F)}{P(F)}, P(F) \neq 0$