**Click Here for**

**JEE main Previous Year Topic Wise Questions of Physics with Solutions**

**Download eSaral app for free study material and video tutorials.**

*Simulator***Previous Years JEE Advanced Questions**

Q. A piece of wire is bent in the shape of a parabola y = $\mathrm{Kx}^{2}$ (y-axis vertical) with a bead of mass m on it. The bead can slide on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now accelerated parallel to the x-axis with a constant acceleration a. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the y-axis is

**[IIT-JEE-2009]**(A) $\frac{\mathrm{a}}{\mathrm{gk}}$ (B) $\frac{\mathrm{a}}{2 \mathrm{gk}}$ (C) $\frac{2 \mathrm{a}}{\mathrm{gk}}$ (D) $\frac{\mathrm{a}}{4 \mathrm{gk}}$**Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(B) $\operatorname{ma} \cos \theta=\operatorname{mg} \sin \theta$ $\mathrm{a}=\mathrm{g} \tan \theta$ $\frac{a}{g}=\tan \theta$ $\frac{a}{g}=2 k x$ $\frac{a}{2 g k}=x$

Good

Jee mains proration

only one

What should I do with one problem? My teacher recommends at least 50 advance level questions per chapter.

Opps!!🙆🏻♀️🙆🏻♀️ the question no is very low we need more ….man

Opps!!🙆🏻♀️🙆🏻♀️ the question no is very low we need more ….

Hay

The hell man

Only one problem

Hello

What the hell

Only one problem

What the hell!

Only one problem………..

Iwill change something great