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**Previous Years JEE Advanced Questions**

** [IIT-JEE-2009]**

(A) $\frac{\mathrm{a}}{\mathrm{gk}}$ (B) $\frac{\mathrm{a}}{2 \mathrm{gk}}$ (C) $\frac{2 \mathrm{a}}{\mathrm{gk}}$ (D) $\frac{\mathrm{a}}{4 \mathrm{gk}}$

**Sol.**(B)

$\operatorname{ma} \cos \theta=\operatorname{mg} \sin \theta$

$\mathrm{a}=\mathrm{g} \tan \theta$

$\frac{a}{g}=\tan \theta$

$\frac{a}{g}=2 k x$

$\frac{a}{2 g k}=x$