*Simulator***Previous Years AIEEE/JEE Mains Questions**

Q. The surface of a metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. The work function of the metal is : (hc = 1240 eV-nm)
(1) 1.51 eVย ย ย ย ย ย (2) 1.68 eVย ย ย ย ย (3) 3.09 eVย ย ย ย ย ย ย (4) 1.41 eV

**[AIEEE – 2009]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(4) $\mathrm{E}_{\mathrm{k}}=\frac{\mathrm{hc}}{\lambda}-\phi_{0} \Rightarrow 1.68=\frac{12400}{4000}-\phi_{0}$ By solving it $\phi_{0}=1.42 \mathrm{eV}$

Q.

**Statement-1 :**When ultraviolet light is incident on a photocell, its stopping potential is V0 and the maximum kinetic energy of the photoelectrons is $\mathrm{K}_{\mathrm{max}}$. When the ultraviolet light is replaced by X-rays, both $\mathrm{V}_{0}$ and $\mathrm{K}_{\mathrm{max}}$ increase.**Statement-2 :**Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light (1) Statementโ1 is true, Statementโ2 is false (2) Statementโ1 is true, Statementโ2 is true; Statementโ2 is the correct explanation of Statementโ 1 (3) Statementโ1 is true, Statementโ2 is true; Statementโ2 is not the correct explanation of Statementโ 1 (4) Statementโ1 is false, Statementโ2 is true**[AIEEE – 2010]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(1) Speed of emitted electrons is independent of frequency of incident light.

Q. This question has Statememtn-1 and Statement-2. Of the four choices given after the statements, choose the one that best describes the two statements.

**Statementโ1 :**A metallic surface is irradiated by a monochromatic light of frequency $\mathrm{v}>\mathrm{v}_{0}$ (the threshold frequency). The maximum kinetic energy and the stopping potential are $\mathrm{K}_{\max }$ and $\mathrm{V}_{0}$ respectively. If the frequency incident on the surface is doubled, both the $\mathrm{K}_{\max }$ and $\mathrm{V}_{0}$ are also boubled.**Statement-2 :**The maximum kinetic energy and the stopping potential of photoelectrons emitted from a surface are linearly dependent on the frequency of incident light. (1) Statementโ1 is true, Statementโ2 is true, Statementโ2 is not the correct explanationof Statementโ 1 (2) Statementโ1 is false, Statementโ2 is true (3) Statementโ1 is true, Statementโ2 is false (4) Statementโ1 is true, Statementโ2 is true, Statementโ2 is the correct explanation of Statementโ 1**[AIEEE-2011]**
Q. The anode voltage of photocell is kept fixed. The wavelength $\lambda$ of the light falling on the cathode is gradually changed. The plate current I of the photocell varies as follows

**[AIEEE-2013]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(4) For constant intensity as wavelength decreases energy of photons increases and number of photons decreases. So it may seem that current should decrease. But the probability that a photon will be successful in emitting an electron will also increase. So as wavelength decreases current increases

Q. Radiation of wavelength $\lambda$, is incident on a photocell. The fastest emitted electron has speed v. If the wavelength of changed to $\frac{3 \lambda}{4}$, the speed of the fastest emitted electron will be :-

**[JEE Main-2016]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(2) $\mathrm{E}=(\mathrm{KE})_{\max }+\mathrm{f}$ $\left[\frac{\mathrm{hc}}{\lambda}=(\mathrm{KE})_{\max }+\phi\right] \ldots .$ (1) \frac{4}{3} \frac{\mathrm{hc}}{\lambda}=\left(\frac{4}{3} \mathrm{KE}_{\max }+\frac{\phi}{3}\right)+\phi

Excellent excellent excellent and very excellent this aap really 100+1%is super aap

All old paper questions

the coding is horrible , hire some real developers

WTF????????????????????

MAINTAIN INDENTATION

LIKE THIS

Statement type question are tougher than numerical type question

bruh

JUST STARTED WITH THE TOPIC…THE QUESTIONS SEEM QUITE EASY…

BUT THANKYOU SO MUCH !

Easyiest question ever๐ ๐

Nice start to encourage jee aspirants with previous year questions

PRISTIGIOUS QUESTION

Kya Maal hai bhaisaab?

Something error

Fantastic