Question:
12 Packets of salt, each marked 2 kg, actually contained the following weights (in kg) of salt:
1.950, 2.020, 2.060, 1.980, 2.030, 1.970,
2.040, 1.990, 1.985, 2.025, 2.000, 1.980.
Out of these packets, one packet is chosen at random.
What is the probability that the chosen packet contains more than 2 kg of salt?
Solution:
Total number of salt packets = 12
Number of packets which contains more than 2 kg of salt = 5
$\therefore P($ Chosen packet contains more than $2 \mathrm{~kg}$ of salt $)=\frac{\text { Number of packets which contains more than } 2 \mathrm{~kg} \text { of salt }}{\text { Total number of salt packets }}=\frac{5}{12}$
Thus, the probability that the chosen packet contains more than $2 \mathrm{~kg}$ of salt is $\frac{5}{12}$.