**Question:**

12 Packets of salt, each marked 2 kg, actually contained the following weights (in kg) of salt:

1.950, 2.020, 2.060, 1.980, 2.030, 1.970,

2.040, 1.990, 1.985, 2.025, 2.000, 1.980.

Out of these packets, one packet is chosen at random.

What is the probability that the chosen packet contains more than 2 kg of salt?

**Solution:**

Total number of salt packets = 12

Number of packets which contains more than 2 kg of salt = 5

$\therefore P($ Chosen packet contains more than $2 \mathrm{~kg}$ of salt $)=\frac{\text { Number of packets which contains more than } 2 \mathrm{~kg} \text { of salt }}{\text { Total number of salt packets }}=\frac{5}{12}$

Thus, the probability that the chosen packet contains more than $2 \mathrm{~kg}$ of salt is $\frac{5}{12}$.

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