A body weighs 49 N on a spring balance at the north pole.

Question:

A body weighs $49 \mathrm{~N}$ on a spring balance at the north pole. What will be its weight recorded on the same weighing

machine, if it is shifted to the equator? [Use $\mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}^{2}}=9.8 \mathrm{~ms}^{-2}$ and radius of earth, $\left.\mathrm{R}=6400 \mathrm{~km} .\right]$

  1. (1) $49 \mathrm{~N}$

  2. (2) $49.83 \mathrm{~N}$

  3. (3) $49.17 \mathrm{~N}$

  4. (4) $48.83 \mathrm{~N}$


Correct Option: , 4

Solution:

(4)

At north pole, weight $\mathrm{M}_{\mathrm{B}}=49$

Now, at equator $g^{g}=g-\omega^{2} R$.

$\Rightarrow M g^{\prime}=M\left(g-\omega^{2} R\right)$

$\Rightarrow$ weight will be less than $\mathrm{Mg}$ at equator.

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now