Question:
A body weighs $49 \mathrm{~N}$ on a spring balance at the north pole. What will be its weight recorded on the same weighing
machine, if it is shifted to the equator? [Use $\mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}^{2}}=9.8 \mathrm{~ms}^{-2}$ and radius of earth, $\left.\mathrm{R}=6400 \mathrm{~km} .\right]$
Correct Option: , 4
Solution:
(4)
At north pole, weight $\mathrm{M}_{\mathrm{B}}=49$
Now, at equator $g^{g}=g-\omega^{2} R$.
$\Rightarrow M g^{\prime}=M\left(g-\omega^{2} R\right)$
$\Rightarrow$ weight will be less than $\mathrm{Mg}$ at equator.
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