A cylindrical tub of radius 12 cm contains water to a depth of 20 cm.

Question:

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 6.75 cm. What is the radius of the ball?

Solution:

Suppose that the radius of the ball is r cm.
Radius of the cylindrical tub =12 cm
Depth of the tub= 20 cm
Now, volume of the ball = volume of water raised in the cylinder

$\Rightarrow \frac{4}{3} \pi r^{3}=\pi \times 12^{2} \times 6.75$

$\Rightarrow r^{3}=\frac{144 \times 6.75 \times 3}{4}=36 \times 6.5 \times 3=729$

$\Rightarrow r=9 \mathrm{~cm}$

∴ The radius of the ball is 9 cm.

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