Question:
A die is thrown. Find the probability of getting a multiple of 3
Solution:
We know that,
Probability of occurrence of an event
$=\frac{\text { Total no. of Desired outcomes }}{\text { Total no. of outcomes }}$
As 3,6 are multiples up to 6, so the desired outcomes are 3,6, and total outcomes are $1,2,3,4,5,6$
Therefore, total no. of outcomes are 6, and total no. of desired outcomes are 2
Probability of getting multiple of 3
$=\frac{2}{6}$
$=\frac{1}{3}$
Conclusion: Probability of getting multiple of 3 when die is thrown is $\frac{1}{3}$
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