# A geostationary satellite

Question:

A geostationary satellite is orbiting around an arbitary planet 'P' at a height of $11 \mathrm{R}$ above the surface of ' $P^{\prime}$, $R$ being the radius of ' $P$ '. The time period of another satellite in hours at a height of $2 R$ from the surface of 'P' is ____________'P' has the time period of 24 hours.

1. $6 \sqrt{2}$

2. $\frac{6}{\sqrt{2}}$

3. 3

4. 5

Correct Option: , 3

Solution:

(3) $\mathrm{T} \propto \mathrm{R}^{3 / 2}$

$\frac{24}{T}=\left(\frac{12 R}{3 R}\right)^{3 / 2} \Rightarrow T=3 h r$