Question:
A man goes 12 m due south and then 35 m due west. How far is he from the starting point?
Solution:
In right triangle SOW
By using Pythagoras theorem, we have
$\mathrm{OW}^{2}=\mathrm{WS}^{2}+\mathrm{SO}^{2}$
$=35^{2}+12^{2}$
$=1225+144$
$=1369$
$\therefore \mathrm{OW}^{2}=1369$
$\Rightarrow \mathrm{OW}=37 \mathrm{~m}$
Hence, the man is 37 m away from the starting point.
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