A man has to go 50m due north,

Question:

A man has to go 50m due north, 40m due east and 20m due south to reach a field.

(a) What distance he has to walk to reach the field?

(b) What is his displacement from his house to the field?

Solution:

(a) Distance travelled = 50+40+20 =110m

(b) Displacement = 50 ĵ +40 î- 20ĵ

= 40î+30 ĵ

$|\operatorname{disp}|=\sqrt{(40)^{2}+(30)^{2}}$

$=50 \mathrm{~m}$ at an angle of $\Theta=\tan ^{-1}\left(\frac{30}{40}\right)=37^{\circ}$ north to east

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