Question:
A mixture of one mole each of $\mathrm{H}_{2}, \mathrm{He}$ and $\mathrm{O}_{2}$ each are enclosed in a cylinder of volume $V$ at temperature $T$. If the partial pressure of $\mathrm{H}_{2}$ is $2 \mathrm{~atm}$, the total pressure of the gases in the cylinder is :
Correct Option: 1
Solution:
$P_{\mathrm{gas}}=\frac{n_{\mathrm{gas}} R T}{V}$
As $n, T$ and $V$ constant so $P_{\mathrm{H}_{2}}=P_{\mathrm{O}_{2}}=P_{\mathrm{He}}=2 \mathrm{~atm}$
So, $P_{\text {Total }}=P_{\mathrm{H}_{2}}+P_{\mathrm{O}_{2}}+P_{\mathrm{He}}=6 \mathrm{~atm}$
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