Question:
A month is selected at random in a year. The probability that it is March or October, is
(a) $\frac{1}{12}$
(b) $\frac{1}{6}$
(c) $\frac{3}{4}$
(d) None of these
Solution:
GIVEN: A month is selected at random in a year.
TO FIND: Probability that it is March or October
Total months in a year is 12
Hence total number of favorable outcome is 2 i.e. March or October
We know that PROBABILITY = 
Hence probability that the month selected is March or October is equal to 
Hence the correct option is
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