A natural number, when increased by 12,


A natural number, when increased by 12, equals 160 times its reciprocal.Find the number.


Let the natural number be x.

According to the question,


On multiplying by $x$ on both sides, we get

$\Rightarrow \quad x^{2}+12 x-160=0$

$x^{2}+(20 x-8 x)-160=0$

$\Rightarrow \quad x^{2}+20 x-8 x-160=0$ [by factorisation method]

$\Rightarrow \quad x(x+20)-8(x+20)=0$

$\Rightarrow \quad ; \quad(x+20)(x-8)=0$

Now, x + 20 = 0 ⇒ x = – 20 which is not possible because natural number is always greater than zero and x-8 = 0⇒x = 8.

Hence, the required natural number is 8.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now