A pack of cards has one card missing. Two cards are drawn randomly and are found to be spades. The probability that the missing card is not a spade, is :
Correct Option: , 3
$\mathrm{E}_{1}$ : Event denotes spade is missing
$\mathrm{P}\left(\mathrm{E}_{1}\right)=\frac{1}{4} ; \mathrm{P}\left(\overline{\mathrm{E}}_{1}\right)=\frac{3}{4}$
A: Event drawn two cards are spade
$\mathrm{P}(\mathrm{A})=\frac{\frac{1}{4} \times\left(\frac{12 \mathrm{C}_{2}}{51 \mathrm{C}_{2}}\right)+\frac{3}{4} \times\left(\frac{13 \mathrm{C}_{2}}{51 \mathrm{C}_{2}}\right)+\frac{3}{4} \times\left(\frac{13 \mathrm{C}_{2}}{51 \mathrm{C}_{2}}\right)}{\frac{1}{4} \times\left(\frac{12 \mathrm{C}_{2}}{51 \mathrm{C}_{2}}\right)+\frac{3}{4} \times\left(\frac{13 \mathrm{C}_{2}}{51 \mathrm{C}_{2}}\right)}$
$=\frac{39}{50}$
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