A particle of mass


A particle of mass ' $m$ ' is projected with a velocity $\mathrm{v}$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height ' $h$ ' is :-

  1. $\frac{\sqrt{3}}{2} \frac{\mathrm{mv}^{2}}{\mathrm{~g}}$

  2. zero

  3. $\frac{m v^{3}}{\sqrt{2} g}$

  4. $\frac{\sqrt{3}}{16} \frac{m v^{3}}{g}$

Correct Option: , 4


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now