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# A particle of mass

Question:

A particle of mass ' $m$ ' is projected with a velocity $\mathrm{v}$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height ' $h$ ' is :-

1. $\frac{\sqrt{3}}{2} \frac{\mathrm{mv}^{2}}{\mathrm{~g}}$

2. zero

3. $\frac{m v^{3}}{\sqrt{2} g}$

4. $\frac{\sqrt{3}}{16} \frac{m v^{3}}{g}$

Correct Option: , 4

Solution: