Question:
A particle of mass ' $m$ ' is moving with speed ' $2 v$ ' and collides with a mass ' $2 m$ ' moving with speed ' $v$ ' in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass ' $m$ ', which move at angle $45^{\circ}$ with respect to the original direction.
The speed of each of the moving particle will be:
Correct Option: , 2
Solution:
(2) $m(2 v)+2 m v=0+2 m v^{\prime} \cos 45^{\circ}$
or $v^{\prime}=2 \sqrt{2} v$
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