Question:
A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?
Solution:
Radius of the bowl, $r=\frac{7}{2} \mathrm{~cm}$
Height of soup in the bowl, h = 4 cm
Volume of soup in one bowl $=\pi r^{2} h=\frac{22}{7} \times\left(\frac{7}{2}\right)^{2} \times 4=154 \mathrm{~cm}^{3}$
∴ Amount of soup the hospital has to prepare daily to serve 250 patients
= Volume of soup in one bowl × 250
= 154 × 250
= 38500 cm3
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.