Question:
A prism of angle $\mathrm{A}=1^{\circ}$ has a refractive index $\mu=1.5$. A good estimate for the minimum angle of deviation (in degrees) is close to $N / 10$. Value of $N$ is___________
Solution:
(5)
Given, Angle of prism, $A=1^{\circ}$
Refractive index of prism, $\mu=1.5$
For a thin prism, minimum angle of deviation is given by
$\delta=(\mu-1) A$
$\Rightarrow \delta=(1.5-1) \times 1^{\circ}=\frac{1}{2}=\frac{5}{10}$
$\Rightarrow N=5$