Question:
A proton, a neutron, an electron and an α-particle have the same energy. Then their de Broglie wavelengths compare as
(a) λp = λn > λe > λα
(b) λα < λp = λn < λe
(c) λe < λp = λn > λα
(d) λe = λp = λn = λα
Solution:
The correct answer is (b) λα < λp = λn < λe
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.