A rectangular plot is given for constructing a house, having a measurement of 40 m

Question:

A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3-m-wide space should be left in the front and back each and 2 m wide space on each of the other sides. Find the largest area where house can be constructed.

Solution:

Let ABCD be a rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front.

According to the laws, the length of the inner rectangle = 40 − 3 − 3 = 34 m and the breath of the inner rectangle = 15 − 2 − 2 = 11 m.

∴ Area of the inner rectangle PQRS = Length × Breath
= 34 × 11
= 374 m2

Hence, the largest area where house can be constructed is 374 m2.

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