Question:
A solution containing $2.675 \mathrm{~g}$ of $\mathrm{CoCl}_{3} .6 \mathrm{NH}_{3}\left(\right.$ molar mass $=267.5 \mathrm{~g} \mathrm{~mol}^{-1}$ ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of $\mathrm{AgNO}_{3}$ to give $4.78 \mathrm{~g}$ of $\mathrm{AgCl}$ (molar mass $=143.5 \mathrm{~g} \mathrm{~mol}^{-1}$ ). The formula of the complex is :-
Correct Option: , 2
Solution:
Solution not required
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