Question:
A steel ball initially at a pressure of $1.0^{\times 10^{5}} \mathrm{~Pa}$ is heated from $20^{\circ} \mathrm{C}$ to $120^{\circ} \mathrm{C}$ keeping its volume constant. Find the inside the ball. Coefficient of linear expansion of steel $=12^{\times 10^{-6} /{ }^{\circ} \mathrm{C}}$ and bulk modulus of steel $=1.6^{\times 10^{11} \mathrm{~N} / \mathrm{m}^{2}}$.
Solution:
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.