Question:
A tower stand vertically on the ground. From a point on the ground 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?
Solution:
Let be the tower of height m and C be the point on the ground, makes an angle of elevation with the top of tower.
In a triangle, given that BC = 20 m and
Now we have to find height of tower, so we use trigonometrical ratios.
In the triangle,
$\Rightarrow \tan C=\frac{A B}{B C}$
$\Rightarrow \sqrt{3}=\frac{h}{20}$
$\Rightarrow h=20 \sqrt{3}$
Hence height of tower is $20 \sqrt{3}$ meters.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.