Question:
An arc of length 15 cm subtends an angle of 45° at the centre of a circle. Find in terms of π, the radius of the circle.
Solution:
We know that the arc length l of a sector of an angle θ in a circle of radius r is
$l=\frac{\theta}{360^{\circ}} \times 2 \pi r$
It is given that $l=15 \mathrm{~cm}$ and angle $\theta=45^{\circ}$.
Now we substitute the value of l and θ in above formula to find the value of radius r of circle.
$15 \mathrm{~cm}=\frac{45^{\circ}}{360^{\circ}} \times 2 \pi r$
$r=\frac{15 \times 360^{\circ}}{2 \pi \times 45^{\circ}} \mathrm{cm}$
$r=\frac{60}{\pi} \mathrm{cm}$