An NCC parade is going at a uniform speed of

For berry,

$u=0 ; a=g ; s=12.1 m$

$\mathrm{s}=\mathrm{ut+}{ }^{\frac{1}{2}} a \mathrm{t}^{2}$

$12.1=0+\frac{1}{2}(g) t^{2}$

$\mathrm{t}=1.57 \mathrm{sec}$

Distance moved by cadets $=\mathrm{v} \times \mathrm{t}$

$=\left(6^{\times \frac{5}{18}}\right)(1.57)$

$=2.6 \mathrm{~m}$

The cadet, $2.6 \mathrm{~m}$ away from tree will receive berry on his uniform