An object, moving with

Question:

An object, moving with a speed of $6.25 \mathrm{~m} / \mathrm{s}$, is decelerated at a rate given by $\frac{\mathrm{dv}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ where $v$ is the instantaneous speed. The time taken by the object, to come to rest, would be :-

  1. $4 \mathrm{~s}$

  2. $8 \mathrm{~s}$

  3. $1 \mathrm{~s}$

  4. $2 \mathrm{~s}$


Correct Option: , 4

Solution:

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